194k views
20 votes
Factor 4x^2-4x-8
Please help

User ValidfroM
by
4.7k points

2 Answers

8 votes

Answer:

4(x+1)x(x-2)

Explanation:

Step 1: factor it

4(x^2-x-2)

Step 2: re write the expression and make -x as a difference

4(x^2+x-2x-2)

Step 3: factor out x from the expression

4(x *(1+1)-2(x+1))

Step 4: factor out x+1 from the expression

4(x+1) x (x-2)

Das it hope you have a good day lol

User Ben Stock
by
5.3k points
7 votes

Answer:

4x² - 4x - 8 can be factored into 4(x - 2)(x + 1)

Explanation:

First, we can factor out 4, as all terms are divisible by that:

4x² - 4x - 8

= 4(x² - x - 2)

Now we need to find two numbers that are are factors of -2, but add up to -1. -2 and 1 meet that condition, so let's split the middle term into those coefficients:

=4(x² + x - 2x - 2)

= 4( x(x + 1) - 2(x - 1) )

= 4(x - 2)(x + 1)

User Damiankolasa
by
5.5k points