Answer: ∠C<∠B<∠A
Explanation:
Given: In triangle ABC,
AB=11,BC=16, and CA=14
Clearly 11<14<16
Therefore, AB<CA<BC
We know that there is a theorem which says that "If a side of a triangle is longer than the other side, then the angle opposite the longer side will be larger than the angle opposite the shorter side".
Therefore, we have that ∠C<∠B<∠A