Question

Can you please solve this problem it is an exit ticket

Answer 1

The slope of a line through the pair of coordinates is define as the rate of change in y coordinates with respect to x coordinate

So,

`\text{Slope =}(y_2-y_1)/(x_2-x_1)`

1) (2, 10) & (1,5)

`\begin{gathered} \text{Slope =}(y_2-y_1)/(x_2-x_1) \\ \text{From the given coordinates we have :} \\ x_1=2,x_2=1,y_1=10,y_2=5 \\ \text{Subctitute the value} \\ \text{SLope =}(5-10)/(1-2) \\ \text{Slope}=(-5)/(-1) \\ \text{Slope =5} \end{gathered}`

2). (0,2) (-3,2)

`\begin{gathered} \text{Slope =}(y_2-y_1)/(x_2-x_1) \\ \text{From the given coordinates we have :} \\ x_1=0,x_2=-3,y_1=2,y_2=2 \\ \text{Subctitute the value} \\ \text{SLope =}(-3-0)/(2-2) \\ \text{Slope}=(-3)/(0) \\ \text{Slope =}0 \end{gathered}`

3). (-4,0) & (0,-3)

`\begin{gathered} \text{Slope =}(y_2-y_1)/(x_2-x_1) \\ \text{From the given coordinates we have :} \\ x_1=-4,x_2=0,y_1=0,y_2=-3 \\ \text{Subctitute the value} \\ \text{SLope =}(-3-0)/(0-(-4)) \\ \text{Slope}=(-3)/(4) \\ \text{Slope =}-(3)/(4) \end{gathered}`

4). (1,3) & (-2,6)

`\begin{gathered} \text{Slope =}(y_2-y_1)/(x_2-x_1) \\ \text{From the given coordinates we have :} \\ x_1=1,x_2=-2,y_1=3,y_2=6 \\ \text{Subctitute the value} \\ \text{SLope =}(6-3)/(-2-1) \\ \text{Slope}=(3)/(-3) \\ \text{Slope =}-1 \end{gathered}`