5.9k views
2 votes
A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?

User Gaby Solis
by
7.8k points

2 Answers

6 votes

Answer:

2400

Step-by-step explanation: i got it right

User Vincent Yin
by
8.2k points
0 votes

Answer:

The total possible outcomes that exist are:

2400

Explanation:

We are given four dices:

first is a standard 6-faced die.

The second die has 4 faces.

Third dice has 10 faces.

Fourth dice has 10 faces.

Now when all the dice are thrown together then the total number of possible outcomes are:


4* 6* 10* 10=2400

( Since there are 4 numbers possible for the first die, 6 for second and 10 each for third and fourth)

The answer is:

2400

User Dylan Jackson
by
8.5k points