Question

A circuit consists of a series combination of 6.50-k\Omega and 5.00-k\Omega resistors connected across a 50.0-{\rm V} battery having negligible internal resistance. You want to measure the true potential difference (that is, the potential difference without the meter present) across the 5.00-k\Omega resistor using a voltmeter having an internal resistance of 10.0 \rm k \Omega.

What potential difference does the voltmeter measure across the 5.00-k\Omega resistor?

What is the true potential difference across this resistor when the meter is not present?

Answer 1

The potential difference that the voltmeter measure across the 5.00-k/Omega resistor would be :
0.004 A
and The true potential difference across the resistor when the meter is not present is :
21.74 V

Hope this helps