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How to find x in cos2x = 3/4? Please explain in detail.
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How to find x in cos2x = 3/4? Please explain in detail.

User Jeerbl
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1 Answer

5 votes
cos2x = 2cos^2 x-1 = 3/4

2cos^2x = 3/4 +1 = 7/4

cos^2x = 7/8

Taking square root

cosx = 0.93541

x = 20.705

Hope this helps
User Bxshi
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