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Find the holes of
f(x) = (3x^2+2x-1)/(x^2-1)

User MightySeal
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1 Answer

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just factor them out

f(x) = (3x - 1) / (x-1)

f (-1) = 3 (-1) - 1 / -1 - 1

f (-1) = -3-1 / -1 -1

f (-1) = -4/2

f (-1) = 2

Hope this helps
User Mtbkrdave
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