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Sam's bike tire contains 15 units of air particles and has a volume of 160mL. Under these conditions the pressure reads 13 psi. The tire develops a leak. Now it contains 10 units of air particles and has
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May 12, 2017
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Sam's bike tire contains 15 units of air particles and has a volume of 160mL. Under these conditions the pressure reads 13 psi. The tire develops a leak. Now it contains 10 units of air particles and has contracted to a volume of 150mL. What would the tire pressure be now?
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Use ideal gas equation, with T constant.
pV =nRT => pV / n = RT = constant
n = K* [units of particles]
pV / [units of particles] = constant
13 psi * 160 mL / 15 units = p * 150 mL / 10 units =>
=> p = [13psi*160mL/15units]*[10units/150mL] = 9.2 psi
Chris Page
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May 17, 2017
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