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Derivative of arcsin(cos(2x))
is this chain rule?

User DigTheDoug
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1 Answer

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Yes, you need to use the chain rule. Also you need to use the derivative of arcsin which is in tables.

Derivative of y = arcsin(x) = 1 / [√(1 - x^2)]

Chain rule: Derivative of archsin(cos(2x)) =

y' = 1 / [√(1 - (cos(2x))^2)] * derivative (cos(2x) =

y' = 1 / [√(1 - (cos(2x))^2)] * (- sin (2x)) * 2

y' = -2(sin(2x)) / [√( 1 - (cos(2x))^2]



User Vntstudy
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