Question

The force F1, 10.0N acts at 10.0cm. What is the magnitude of the torque due to F1 about an axis through Point A perpendicular to the page? Is it clockwise,or is it counterclockwise? ( Point A is at 0 on a meter stick. There is also a point B at 50cm and F2 is 70cm with a force of 15.0N)

Answer 1

torque = F*r*sin(90)
=10N*.1m*1 = 1Nm
direction of torque would be into the screen (clockwise rotation)