Question

Two violin strings are tuned to the same frequency, 277 Hz. The tension in one string is then decreased by 1.92 percent. What will be the beat frequency heard when the two strings are played together?

Answer 1

the recurrence of the two strings is relative to the squareroot of the pressure. So if the strain is decreased by what might as well be called .0192 then .9808 speaks to the part of the pressure remaining. considering everything else will continue as before the resutling recurrence will be .990 of the orginal recurrence which is 274 Hz the distinction being 3 Hz as indicated by adjustment hypothesis the distinction of the two frequencies gives the recurrence of beating which for this situation is three beats for each second. Trust this makes a difference.