Question

A ball is thrown at an angle of 25 degrees to the horizon. The ball has a horizontal velocity component of 12.5 m/s. Find the vertical velocity component of the ball and the magnitude of the actual velocity. How high would the ball travel before it begins to come down again?

Answer 1

horizontal velocity is 12.5m/s

Magnitude of actual velocity we find like this:
cos25*Vm=12,5
Vm = 12,5/cos25
Vm= 13.8m/s

vertical velocity is:
Vv = Vm*sin25 = 5.83m/s

Time after ball will stop ascending is:
t=Vv/a = 5,83/9.81 = 0.59s

Finally we calculate traveled distance:
S=t*Vh = 0.59*12,5 = 7.42m