Answer:
A. NaOH
Step-by-step explanation:
The reaction of these ions with the following reactants produce:
A. NaOH
Pb(OH)₂ insoluble
Ba(OH)₂ soluble
The addition of NaOH will precipitate Pb²⁺ as Pb(OH)₂ and Ba²⁺ will remain in solution
B. Na₂SO₄
PbSO₄ insoluble
BaSO₄ insoluble
Both Pb²⁺ and Ba²⁺ will precipitate in an aqueous solution
C. K₃PO₄
Pb₃(PO₄)₂ insoluble
Ba₃(PO₄)₂ insoluble
Both Pb²⁺ and Ba²⁺ will precipitate in an aqueous solution
D. K₂CO₃
PbCO₃ insoluble
BaCO₃ insoluble
Both Pb²⁺ and Ba²⁺ will precipitate in an aqueous solution
E. Ca(CH₃CO₂)₂
Pb(CH₃CO₂)₂ soluble
Ba(CH₃CO₂)₂ soluble
Both Pb²⁺ and Ba²⁺ will remain in an aqueous solution
I hope it helps!