Question

Aqueous sodium chloride reacts with aqueous lead (II) nitrate to yield a lead(II) chloride precipitate and aqueous sodium nitrate.

can you translate this to chemical equations

Answer 1

Aqueous sodium chloride reacts with aqueous lead (II) nitrate to form a precipitate of lead (II) chloride and an aqueous solution of sodium nitrate, represented by the balanced chemical equation: Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq).

Step-by-step explanation:

When aqueous sodium chloride reacts with aqueous lead (II) nitrate, a chemical reaction occurs known as a double-replacement reaction. The result of this reaction is the formation of a lead (II) chloride precipitate and an aqueous solution of sodium nitrate. The balanced chemical equation for this reaction is:

Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2 (s) + 2 NaNO3(aq)

This indicates that one mole of lead (II) nitrate reacts with two moles of sodium chloride to produce one mole of lead (II) chloride, which precipitates out of the solution, and two moles of sodium nitrate, which remains in the aqueous phase.

Answer 2

the chemical equations for:
aqueous sodium chloride reacts with aqueous lead, nitrate to yield a lead, chloride precipitate and aqueous sodium nitrate are:

Ba(NO3)2 (aq) + H2SO4 -> BaSO4 (downward arrow) + 2HNO3 (aq)

Hope this help