Question

Determine the number of moles of N atoms in 46.5g of Mg(NO3)2

Answer 1

To determine the number of moles of N atoms in Mg(NO3)2, calculate the molar mass of Mg(NO3)2 and convert the mass to moles.

Step-by-step explanation:

The number of moles of N atoms in 46.5g of Mg(NO3)2 can be determined by calculating the molar mass of Mg(NO3)2 and then using it to convert the mass of Mg(NO3)2 to moles.

Molar mass of Mg(NO3)2 = (the mass of Mg) + (the number of moles of N atoms in one mole of Mg(NO3)2) + (the number of moles of O atoms in one mole of Mg(NO3)2)

Once the molar mass of Mg(NO3)2 is calculated, use it to convert the mass of Mg(NO3)2 to moles using the formula:

moles = mass / molar mass

Therefore, the number of moles of N atoms in 46.5g of Mg(NO3)2 is:

moles of N atoms = (moles of Mg(NO3)2) * (the number of moles of N atoms in one mole of Mg(NO3)2)

Answer 2

First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
= 0.4 mole

Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
Moles Nitrogen = 0.4 x 2
= 0.8 mole