Question

Calculate the number of C, H, and O atoms in 1.75 g of squaric acid

Answer 1

Number of C atoms = 0.0168 mol * 6.022 x 10^23 atoms/mol = 1.01 x 10^22 atoms

Number of H atoms = 0.0336 mol * 6.022 x 10^23 atoms/mol = 2.02 x 10^22 atoms

Number of O atoms = 0.0336 mol * 6.022 x 10^23 atoms/mol = 2.02 x 10^22 atoms

Step-by-step explanation:

Squaric acid is a compound with the formula C4H2O4. To calculate the number of C, H, and O atoms in 1.75 g of squaric acid, we need to first determine the molar mass of squaric acid. The molar mass can be calculated by summing the atomic masses of each element in the compound:

Molar mass of C: 12.01 g/mol

Molar mass of H: 1.01 g/mol

Molar mass of O: 16.00 g/mol

Total molar mass of squaric acid: (4 * 12.01) + (2 * 1.01) + (4 * 16.00) = 104.08 g/mol

Now we can calculate the number of moles of squaric acid:

Number of moles = given mass / molar mass = 1.75 g / 104.08 g/mol = 0.0168 mol

Since the ratio of atoms in squaric acid is 1:2:2 (C:H:O), we can multiply the number of moles by the respective ratios to find the number of atoms:

Number of C atoms = 0.0168 mol * 1 = 0.0168 mol

Number of H atoms = 0.0168 mol * 2 = 0.0336 mol

Number of O atoms = 0.0168 mol * 2 = 0.0336 mol

Finally, to convert the number of moles to the number of atoms, we multiply by Avogadro's number:

Number of C atoms = 0.0168 mol * 6.022 x 10^23 atoms/mol = 1.01 x 10^22 atoms

Number of H atoms = 0.0336 mol * 6.022 x 10^23 atoms/mol = 2.02 x 10^22 atoms

Number of O atoms = 0.0336 mol * 6.022 x 10^23 atoms/mol = 2.02 x 10^22 atoms

Answer 2

As far as I remember, the needed formula for squaric acid is C4H2O4.
According to this one mole should be 114.06 g., which means we have 0.015mol of this acid.
Then we can easly calculate : 4(0.015) = 0.06 mol for both for Carbon and Oxygen and 0.03 mol of Hydrogen.
To get more clear answer, we multiply by avogadros :
6.022 x 10^23. Hope everything is clear! regards