149k views
1 vote
If L is the line through the point (- 3, 5) having a slope of , complete the equation of L.

y =


(2/3)x + 7
(2/3)x + (47/9)
(2/3)x - (1/3)

2 Answers

7 votes

Answer:

To complete the equation of line L that passes through the point (-3, 5) and has a slope of 2/3, we can use the point-slope form of a linear equation:

y - y₁ = m(x - x₁)

Where:

- (x₁, y₁) is the given point (-3, 5).

- m is the slope, which is 2/3.

Substitute the values:

y - 5 = (2/3)(x - (-3))

Simplify the expression:

y - 5 = (2/3)(x + 3)

Distribute (2/3):

y - 5 = (2/3)x + 2

Now, isolate y by adding 5 to both sides:

y = (2/3)x + 2 + 5

y = (2/3)x + 7

So, the correct equation of line L is:

y = (2/3)x + 7

Among the options you provided, the correct equation is indeed:

y = (2/3)x + 7

User Rahul Rajan
by
8.2k points
2 votes
y - 5 = 2/3(x + 3)
y - 5 = 2/3x + 2
y = 2/3x + 2 + 5
y = 2/3x + 7
User Shaun Wild
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories