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1 vote
If L is the line through the point (- 3, 5) having a slope of , complete the equation of L.

y =


(2/3)x + 7
(2/3)x + (47/9)
(2/3)x - (1/3)

2 Answers

7 votes

Answer:

To complete the equation of line L that passes through the point (-3, 5) and has a slope of 2/3, we can use the point-slope form of a linear equation:

y - y₁ = m(x - x₁)

Where:

- (x₁, y₁) is the given point (-3, 5).

- m is the slope, which is 2/3.

Substitute the values:

y - 5 = (2/3)(x - (-3))

Simplify the expression:

y - 5 = (2/3)(x + 3)

Distribute (2/3):

y - 5 = (2/3)x + 2

Now, isolate y by adding 5 to both sides:

y = (2/3)x + 2 + 5

y = (2/3)x + 7

So, the correct equation of line L is:

y = (2/3)x + 7

Among the options you provided, the correct equation is indeed:

y = (2/3)x + 7

User Rahul Rajan
by
7.1k points
2 votes
y - 5 = 2/3(x + 3)
y - 5 = 2/3x + 2
y = 2/3x + 2 + 5
y = 2/3x + 7
User Shaun Wild
by
6.4k points