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Derivative of square root of (lnx)
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Derivative of square root of (lnx)

User Ivone
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Use the chain rule

y = √[ln(x)]=> y' = [1/2√(lnx)]*[ln(x)]' = [1/2√(lnx) ] * 1/x = 1 / [2x(√lnx)]
User Anj
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