17.7k views
3 votes
A 0.4243-g sample of CaCO 3 is dissolved in 12 M HCl and the resulting solution is diluted to 250.0 mL

in a volumetric flask.How many moles of CaCO 3 are used (formula mass = 1 00.1 )?

User Cheekujha
by
8.8k points

1 Answer

7 votes
Moles = mass / Mr
= 0.4243 / 100.1
= 4.239 x 10⁻³ mole of CaCO₃

User TomRichardson
by
8.1k points