192k views
2 votes
Assume that the box contains 11 balls: 4 red, 4 blue, and 3 yellow. As in the text, you draw one ball, note its color, and if it is yellow replace it. If it is not yellow you do not replace it. You then draw a second ball and note its color.

(1) What is the probability that the second ball drawn is yellow?

(2) What is the probability that the second ball drawn is red?

1 Answer

2 votes
1)

(3)/(11) * (3)/(11) + (8)/(11) * (3)/(10)= (9)/(121)+ (24)/(110) =0.29

2)

(3)/(11) * (4)/(11) +(8)/(11) * (3)/(10) +(8)/(11) * (4)/(10) = (12)/(121)+ (24)/(110) + (32)/(110) = 0.61
Assume that the box contains 11 balls: 4 red, 4 blue, and 3 yellow. As in the text-example-1
Assume that the box contains 11 balls: 4 red, 4 blue, and 3 yellow. As in the text-example-2
User Century Tuna
by
7.9k points

No related questions found