Question

Marble (calcium carbonate) reacts with hydrochloric acid solution to form calcium chloride solution, water, and carbon dioxide. What is the percent yield of carbon dioxide if 3.65 g of the gas is collected when 10.0 g of marble reacts?

Answer 1

To find the percent yield of carbon dioxide, calculate the theoretical yield using stoichiometry and then calculate the percent yield using the actual yield.

Step-by-step explanation:

To find the percent yield of carbon dioxide, we need to compare the actual yield of carbon dioxide to the theoretical yield of carbon dioxide. The theoretical yield can be calculated using stoichiometry.

First, we need to find the number of moles of calcium carbonate in the given 10.0 g. This can be calculated using the molar mass of calcium carbonate. Then, we use the balanced chemical equation to determine the mole ratio between calcium carbonate and carbon dioxide. Finally, we can calculate the theoretical yield of carbon dioxide.

The percent yield is then calculated by dividing the actual yield of carbon dioxide (3.65 g) by the theoretical yield of carbon dioxide and multiplying by 100.

Answer 2

CaCO3+2HCl→CaCl2+H2O+CO2
You have to find which is limiting first, we take 10g of marbles10g marbles×1 mol marbles/40+12+3(16)g marbles×1 mol CO2/1 mol marbles=0.4 mol CO2
Then0.4 mol CO2 ×12+2(16)g CO2/1 mol CO2=17.6g of CO2
Based on theoretical calculations, you should get 17.6g of CO2, but it turns out that you only have 3.65g of CO2 collected, so,3.65g17.6g×100=20.7 percent