Question

A research submarine has a 40.0 -diameter window 8.40 thick. The manufacturer says the window can withstand forces up to 1.20×106 . What is the submarine's maximum safe depth?

Answer 1

First, calculate the pressure at which the window can be exposed, from the force it can withstand and the area. Second, calculate the depth of the sea for the calcualated pressure.

I will assume that the diameter of the window is given in cm and that the force is given in newtons.

1) P = F / A

A = π*r^2 = π(0.20 m)^2 = 0.125664 m^2

P = 1.20 * 10^6 N / 0.125664 m^2 = 9.549*10^6 Pa

2) Conversion: 1 meter of seawater = 10069.3064 Pa

9.549*10^6 Pa * 1 msw / 10069.3064 Pa = 948 msw

Answer: 948 m under the sea