F(x)= 9-x^2, x ≥ 0. f^-1(x)=??

asked May 17, 2017 56.1k views

1 vote

by QKWS

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3 votes

$y=9-x^(2),\ x\ge0$

Reverse

and

:

$x=9-y^(2),\ y\ge0$
Solve for

$\rightarrow y^(2)=9-x$

$\rightarrow y=√(9-x)$ since
$y\ge0$

Stames answered May 23, 2017

9.0k points

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