Question

Solve the exponential equation algebraically

Answer 1

hmm, ok

so rememeber

`log_ab=c` means
`a^c=b`
therefor


`a^c=b` is to
`2^x=33`
as is

`log_ab=c` is to
`log_233=x`

x=
`log_233` or aprox 5.04439

Answer 2

2^x=33
log2^x=log33
xlog2=log33
(xlog2)/log2 = (log33)/log2
x=(log33)/log2= 5.04439411936