Question

Which product of prime polynomials is equivalent to 8x3 – 2x?

x(2x – 1)(2x – 1) 2x(x + 1)(x – 1) 2x2(2x + 1)(2x – 1) 2x(2x + 1)(2x – 1)

Answer 1

2x(2x + 1)(2x - 1) =
2x(4x^2 - 1) =
8x^3 - 2x

Answer 2

2x(2x+1)(2x-1)

Explanation:

We have been given the polynomial

`8x^3-2x`

We will take common factor out which is 2x

`2x(4x^2-1)`

Now, using
`a^2-b^2=(a+b)(a-b)`

`a=2x\text{and}b=1`

`4x^2-1=(2x-1)(2x+1)`

So, given polynomial is equivalent to: 2x(2x+1)(2x-1)

Therefore, last option is correct.