98.7k views
5 votes
The coordinates of the vertices of a polygon are (0,3), (2,3) (2,0), (1,-4) and (-2,-1).

What is the perimeter of the polygon to the nearest tenth of a unit?


A.) 15.8 units


B.) 16.9 units


C.) 17.8 units


D.) 18.6 units

2 Answers

6 votes

For anyone reading in the future, it is 17.8 units.

User B Hart
by
8.8k points
2 votes
Let the cordinates be A(0,3), B(2,3), C(2,0), D(1,-4) and E(-2,-1), then

The perimeter is the sum of the lengths of the line segments joining the coordinates.
Length of AB = 2 units
Length of BC = 3 units
Length of CD = sqrt((1 - 2)^2 + (-4)^2) = sqrt(1 + 16) = sqrt(17) = 4.12 units
Length of DE = sqrt((-1 - (-4))^2 + (-2 - 1)^2) = sqrt(3^2 + (-3)^2) = sqrt(9 + 9) = sqrt(18) = 4.24 units
Length of EA = sqrt((0 - (-2))^2 + (3 - (-1))^2) = sqrt(2^2 + 4^2) = sqrt(4 + 16) = sqrt(20) = 4.47

Therefore, perimeter = 2 + 3 + 4.12 + 4.24 + 4.47 = 17.8 units.
User Radpet
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories