Question

James creates the table shown to represent the function ƒ(x) = x2 - 4x + 3.

Determine the zero(s) of the function.

Answer 1

0=x^2 -4x+3 0=(x+1) (x+3) X+1=0 x=-1 X+3=0 x=-3

Answer 2

The zeros of the given function is 1 and 3

Explanation:

James creates the table shown to represent the function

`f(x)=x^2-4x+3`

Table of f(x)

x | f(x)

-1 | 8

0 | 3

1 | 0

2 | -1

3 | 0

4 | 3

5 | 8

Using table we need to find zeros.

Zeros of the function when function value becomes 0 at given value of x.

So, we will see the table value where f(x) becomes 0

In table we can see f(x) is zero at two value of x

At x=1, f(1)=0

At x=3, f(3)=0

Here we have two zeros at x=1 and 3

Zero: x=1 and x=3

Hence, The zeros of the given function is 1 and 3