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In a physics lab a student discovers that the magnitude of the magnetic field in a specific location near a long wire is 20.004 microTesla. If the wire carries a current of 63.246 A, what is the distance from the wire to that location ?

User Augusto Barreto
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1 Answer

16 votes
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Given:

The magnetic field is B = 20.004 micro Tesla

The current is I = 63.246 A

To find the distance between the wire and the location.

Step-by-step explanation:

The distance can be calculated by the formula


d=(\mu_0I)/(2\pi B)

Here, the constant is


\mu_0=4\pi*10^(-7)\text{ H/m}

On substituting the values, the distance between them will be


\begin{gathered} d=\frac{4\pi*10^(-7)*63.246}{2\pi*20.004*10^(-6)\text{ }} \\ =0.632\text{ m} \end{gathered}

Thus the distance between the wire and the location is 0.632 m

User Tsal Troser
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