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Identify the following series as arithmetic, geometric, both, or neither.

3a + 3a² + 3a³ + . . . + 3an

arithmetic
geometric
both
neither

2 Answers

5 votes

Answer:

Option 2 - Geometric series

Explanation:

Given : Series
3a+3a^2+3a^3+.....+3a^n

To identify : The following series as arithmetic, geometric, both, or neither.

Solution :

According to the series,


3a+3a^2+3a^3+.....+3a^n

If we take 3 common,


=3(a+a^2+a^3+.....+a^n)

the above series make is a geometric series as 3 is a constant.

Geometric series is
\sum_k a_k where ratio of two terms is
(a_(k+1))/(a_k)

In the above given series, the common ratio is a.

As the series satisfy all conditions of geometric series.

Therefore, Option 2 is correct.

User Kmandov
by
6.6k points
6 votes
The expression 3a + 3a² + 3a³ + . . . + 3an is a geometric expression, because 3 is constant.
User Pedrodotnet
by
6.7k points
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