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1 vote
How many permutations exist of the letters a, b, c, d taken three at a time?

24
12
4

User Nema Ga
by
8.5k points

2 Answers

3 votes

Answer:

Option A. 24

Explanation:

There are four letters a, b, c, d and we have to tell the permutations made when taken 3 at a time.

This phenomenon exist =
^(4)P_(3) =
(4!)/((4-3)!)

=
(4!)/(1!) = 4! = 4 × 3 × 2× 1 = 24

Therefore, option (A) 24 are the permutations exist.

User Ashubuntu
by
8.0k points
3 votes
The correct answer is 24

You have to apply factorials here and formulas. You have 4 letters which means that your n=4, and you have 3 objects at a time which, means that you have 4 different groups of combinations with 6 permutations in each due to the 3! factorial. 6 x 4 is 24.
User Kaffee
by
7.4k points

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