Question

The area of a sector of a circle with a central angle

Answer 1

The area sector of a circle is

`A=(\theta)/(360)(\pi r^2)`

where θ = central angle

r = radius of the circle

From the problem, the area is 9 ft^2 and the central angle is 60 degrees

The radius will be :

`\begin{gathered} 9=(60)/(360)(\pi r^2) \\ 9(360)=60\pi r^2 \\ (9(360))/(60\pi)=r^2 \\ r=\sqrt[]{(9(360))/(60\pi)} \\ r=4.146 \end{gathered}`

The answer rounded to the nearest tenth is 4.1 ft