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The function f(x)=tan(3/2x-pi/2) has: A) period pi/3 and asymptote at x=pi/3 B) period 2pi/3 and asymptote at x=0 C) period 2pi/3 and asymptote at x=pi/3 D) period pi/3 and asymptore at x=0
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The function f(x)=tan(3/2x-pi/2) has:

A) period pi/3 and asymptote at x=pi/3

B) period 2pi/3 and asymptote at x=0

C) period 2pi/3 and asymptote at x=pi/3

D) period pi/3 and asymptore at x=0

User Bright
by
7.6k points

2 Answers

5 votes

Answer:

B

Explanation:

A PEx

User Cgons
by
8.3k points
6 votes
I think the best option here is B. period 2pi/3 and asymptote at x=0
because period of tanx is pi so period of tan(3/2x) is pi/(3/2) = 2pi/3. I hope this can work good for you.
User Edwardth
by
8.1k points
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