Question

Find all real numbers X such that
18x-9>9 AND 2x-4>-10

Answer 1

Answer: The answer is x>1

Step-by-step explanation: Given equation:

18x-9>9 .........[1]

AND 2x-4>-10 ........[2]

18x-9>9

Adding 9 both sides

18x-9+9>9+9

=18x>18

Dividing both sides by 18

`(18x)/(18)`>
`(18)/(18)`

=x>1 ........[3]

Now 2x-4>-10

Adding 4 both sides

2x-4+4>-10+4

=2x>-6

Dividing both sides by 2

`(2x)/(2)>(-6)/(2)`

⇒x>-3 .......[4]

On solving [3] we get all real values greater than 1

On solving [4] we get all real values greater than -3

Hence the values common in both is x>1

So the solution set for x is (1,∞)

Answer 2

So what we are going to do is the next thing:
Consider 18x-9>9 1.
add 9 to both sides 2.
divide both sides by the coefficient of x (that is 18 in this case)
Now Consider 2x-4>-10 1.
Then add 4 to both sides 2.
divide both sides by the coefficient of x (that is 2 in this case)
The final solution would be x < 1
Hope this can fit what you are looking for