Question

Find the equation of the line in slope-intercept form that passes through the points (-2,-4) and (-3,2).

Answer 1

`y=-6x-16`

Explanation:

Slope intercept formula:
`y=mx+b`

Slope

Using two points formula:
`\boxed{(y_2-y_1)/(x_2-x_1)}`

Plug the points in and solve:
`(2-(-4))/(-3-(-2))`

`=(6)/(-1)`

`=-6`

m = -6

y-intercept

Plugin one point into the slope-intercept formula with the slope, and solve: (-2, -4)

`-4=-2(-6)+b`

Simplify
`-4=12+b`

Subtract 12 from both sides:
`-4-12=12+b-12`

`=16`

b = -16

Therefore, the equation is
`\bold{y=-6x-16}`