Question

There are a number of fruits in a bag. 2/5 of it is mango and the rest is banana. If 1/3 of the bananas or 12 banana are removed, how many mangoes are in the bag?

Answer 1

Let the number of fruits in the bag be x.

Given:

`\begin{gathered} \text{Mango = }(2)/(5)x \\ \text{Banana = }(3)/(5)x \end{gathered}`

From the statement: 1/3 of the bananas or 12 bananas are removed. We can represent this mathematically as:

`(1)/(3)\text{ }*\text{ }(3)/(5)x\text{ = 12}`

Solving for x:

`\begin{gathered} (1)/(5)x\text{ = 12} \\ \text{Cross}-\text{Multiply} \\ x\text{ = 5 }*\text{ 12} \\ =\text{ 60} \end{gathered}`

Recall that the number of mangoes in the bag is:

`=\text{ }(2)/(5)x`

Substituting:

`\begin{gathered} \text{Number of mangoes = }(2)/(5)\text{ }*\text{ 60} \\ =\text{ 24} \end{gathered}`

Hence, there are 24 mangoes in the bag

Answer:

24 mangoes