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Sodium and oxygen react to produce Sodium oxide. How many moles of oxygen are needed to produce 27.47 grams of Sodium oxide

User Cristian Bitoi
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1 Answer

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Step-by-step explanation:

Sodium and oxygen will react to produce sodium oxide.

sodium + oxygen ---> sodium oxide

The balanced equation will be:

4 Na + O₂ ---> 2 Na₂O

Before we find the moles of oxygen we have to convert the mass of Na₂O to moles. We have to use the molar mass of Na₂O.

molar mass of Na = 22.99 g/mol

molar mass of O = 16.00 g/mol

molar mass of Na₂O = 2 * 22.99 g/mol + 1 * 16.00 g/mol

molar mass of Na₂O = 61.98 g/mol

moles of Na₂O = 27.47 g * 1 mol/(61.98 g)

moles of Na₂O = 0.4432 mol

4 Na + O₂ ---> 2 Na₂O

According to the coefficients of the equation, 4 moles of Na will react with 1 mol of O₂ to produce 2 moles of Na₂O. The molar ratio between O₂ and Na₂O is 1 to 2.

molar ratio 1 mol of O₂ : 2 moles of Na₂O

We can use this relationship to find the number of moles of O₂ that are needed to produce 0.4432 moles of Na₂O.

moles of O₂ = 0.4432 moles of Na₂O * 1 mol of O₂/(2 moles of Na₂O)

moles of O₂ = 0.2216 moles

Answer: 0.2216 moles of oxygen are needed to produce 27.47 g of sodium oxide.

User Taylor Simpson
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