Question

HELP!!! PLEASE!!!

Caluclate how many grams of solid Mg(NO3)2 and Sr(NO3)2 to dissolve in water to make your solutions. Specifically,write out the calculations to prepare 100.0ml of 0.1000M Mg(NO3)2 and 100.0 ml of 0.1000M Sr(NO3)2. --The Mg(NO3)2 supplied comes in the form of Mg(NO3)2 6H2O, use the formula weight 256.4 grams per mole in the calculation for Mg(NO3)2. ...?

Answer 1

Molarity is expressed as the number of moles of solute per volume of the solution. We solve the problem above as follows:

0.1000 mol Mg(NO3)2 / L (.1 L) ( 148.3 g / mol ) = 1.483 g Mg(NO3)2

0.1000 mol Sr(NO3)2 / L (.1 L) ( 211.63 g / mol ) = 2.116 g Sr(NO3)2

Hope this answers the question. Have a nice day.