98.0k views
3 votes
Ln(x)=1.5
solve for x
...?

User Krzydyn
by
8.4k points

2 Answers

0 votes
It is a very simple problem, if you know the way for representing it in a proper manner. There are basically no complications associated with this problem.

Ln(x) = 1.5
Then
x = e^1.5
= 4.48
I hope the procedure is simple enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.
User Fahim Bagar
by
8.2k points
0 votes

Answer:


x=4.48169

Explanation:

We must remember first the definition of logarithm:


log_(b)a=c\\ b^(c)=a

When our base (
b) is
e(Euler's number≈2.72) we write it as


ln(a)=c\\e^(c)=a

Now for our case we have


ln(x)=1.5

we solve for x as we defined before (
x will be our
c and 1.5 will be our
a)
e^(1.5)=x\\x=4.48169

User Swigganicks
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories