Question

Select the inequality that models the problem.

The length of a rectangle is twice its width. If the perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?


2*2w + 2w < 50

2 + 2w < 50

2w*w < 50

2w < 50 ...?

Answer 1

Here is the answer for the given problem above.
We know that the formula for getting the perimeter is P =2W +2L.
Now, it is defined that length of a rectangle is twice its width so this gives us L=2w. And the perimeters is less than 50 meters so it is P < 50.
So the answer for this would be 2(2w) + 2w <50. It would be the first option. Hope this answer helps.