Question

How to distribute this problem:
(x-8)^2 + 16

Answer 1

We conclude that:

`\left(x-8\right)^2+16=x^2-16x+80`

Explanation:

Given the equation

`\left(x-8\right)^2\:+\:16`

First, solve (x - 8)²

Apply Perfect Square formula: (a - b)² = a² - 2ab + b²

`a=x,\:\:b=8`

`\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2`

`=x^2-16x+64`

so the expression becomes

`\left(x-8\right)^2+16=x^2-16x+64+16`

`=x^2-16x+80` Add the numbers: 64+16=80

Therefore, we conclude that:

`\left(x-8\right)^2+16=x^2-16x+80`