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What's the derivative of tan^-1 (lnx) ...?

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Answer:


\displaystyle (dy)/(dx) = (1)/(x \Big( (\ln x)^2 + 1 \Big))

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

Step 1: Define

Identify


\displaystyle y = \arctan (\ln x)

Step 2: Differentiate

  1. Trigonometric Differentiation [Derivative Rule - Chain Rule]:
    \displaystyle y' = ((\ln x)')/((\ln x)^2 + 1)
  2. Logarithmic Differentiation:
    \displaystyle y' = ((1)/(x))/((\ln x)^2 + 1)
  3. Simplify:
    \displaystyle y' = (1)/(x \Big( (\ln x)^2 + 1 \Big))

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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