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A Log floats in a river with one-forth of its volume about the water. (a) what is the density of the log? ...?

User Leafmeal
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This problem can be solved by using the Archimedes Principle. The principle basically lets us derive a force balance between the weight of the log and the buoyant force exerted by the water, that is

weight of log = buoyant force exerted by water

simplification of the derviation would yield,

Dl/Dw = fraction of the of the log submerged in water = (1-0.25) = 0.75

where Dl = density of the log
Dw = density of the water (1000 kg/m3)

therefore Dl = 750 kg/m^3

Hope this helps
User Timmwagener
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