Question

a bowling ball is dropped from a height of 24 feet. write a function that gives the height h (in feet) of the bowling ball after t seconds

Answer 1

gravity pulls at 32 feet per second so it would take .75sec to hit the ground now make an equation that can make this applicable so after .75 second T it would be at 0 feet H

Answer 2

`h=16t^2`

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32 ft/s²

`s=ut+(1)/(2)at^2\\\Rightarrow h=ut+(1)/(2)32* t^2\\\Rightarrow h=ut+16t^2`

Here, u = 0 so,

`h=0t+16t^2\\\Rightarrow h=16t^2`

The equation is
`h=16t^2`

`24=16t^2\\\Rightarrow t=\sqrt{(24)/(16)}\\\Rightarrow t=1.22\ s`

Time taken by the ball to hit the ground is 1.22 seconds