C) 26,000 < (6,182 - 2,306)y
1) Gathering the data
Spent = $6,812 per yer
More efficient car = $26,000
Costs with fuel per year (average) = $2,306
2) So let's write an inequality, where y stands for the number of years that the total amount of fuel savings will exceed the purchase price of the new vehicle.
2306y+
26,0000< 2,306y-6812
Since 6812 y is the expense with fuel yearly, then and 2,306 depends on the number of years then the option is
C) 26,000 < (6,182 - 2,306)y
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