Question

5x + 9y, when x=8, y=11

a 3 –c + b, when a=3, b=6, c=8
4(g –h) +10,when g=12, h=7
4(g –h) +10,when g=12, h=7
k 3 –4j +12, when k=8, j=2
help plssss

Answer 1

Please check the explanation.

Explanation:

Part 1)

5x + 9y, when x=8, y=11

substituting x=8, y=11 in 5x + 9

5x + 9y = 5(8) + 9(11)

= 40 + 99

= 139

Part 2)

a³ –c + b, when a=3, b=6, c=8

substituting a=3, b=6, c=8 in a³ –c + b

a³ –c + b = (3)³ - 8 + 6

= 27 - 2

= 25

Part 3)

4(g –h) +10, when g=12, h=7

substituting g=12, h=7 in 4(g –h) +10

4(g –h) +10 = 4(12 - 7) + 10

= 4(5) + 10

= 20 + 10

= 30

Part 4)

k³ –4j +12, when k=8, j=2

substituting k=8, j=2 in k³ –4j +12

k³ –4j +12 = (8)³ - 4(2) + 12

= 512 - 8 + 12

= 516

Summary: