5x^2-3y^2-20x+6y+2=0 what is the value of a

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asked May 17, 2017 23.0k views

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Macks · Answer 1 · 2017-05-23T13:49:12+0000

What is the value of c? 5x2 - 3y2 - 20x + 6y + 2 = 0 Select one: a. 2 b. 4 c. √4 d. √8 This was an older question and someone said the answer was D and I got it right.

5x^2-3y^2-20x+6y+2=0 what is the value of a

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