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What is the sum of the arithmetic sequence 3,9,15, if there are 36 terms ...?

User Refresh
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1 Answer

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n = 36

a = 3

d = 3

(n/2) (2a + (n - 1)d)

(36/2) (2(3) + (36 - 1)3)

18(6+35(3))

18 x 111 = 1998

The sum is 1998


User Eridanix
by
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