Question

Give the excluded value(s) for the following fraction.

y+5/y^2+4y-32

Answer 1

y is -8 and 4.

Explanation:

Answer 2

Since we can divide by 0, we can clearly see that there is no way denominator can be 0. So, lets start :
`y^2+4y-32=0`.
The exluded values are lying in the y and we hav eto find them :
`y^2+4y-32=(y+8)*(y-4)=0`
According to the info above,
`y+8=0 or y-4=0`
y is -8 and 4.
That's all!