Question

A particle is constrained to move along a straight line through O.

it starts initially at D, which is a fixed distance from O in the positive direction&moves at a constant velocity of 4ms^-1 for 15 sec. until; it is 100m from O for a furhter 25 sec, after which it travels in the opposite direction for 20 sec.
the total distance is 180m.

How far from O does the particle stop?
how do i draw a velocity–time graph?
and what is the final displacement of the particle from its initial position? ...?

Answer 1

x=1.9+2.5t+3.7t2 V=2.5−3.7t V=0 when it stops 0=2.5-7.4t t=0.3378 a) x=1.9+2.5t+3.7t2 (t=0.3378) x=3.1167m b) V=2.5−3.7t (t=0) V=2.5 but because it's returning here velocity is -2.5