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X ^{sqrt{logx}}=10^{8} ...?

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x ^{\sqrt{\log{x}}}=10^(8) \\ \\ \log{x ^{\sqrt{\log{x}}}}=\log{10^(8)} \\ \\ \sqrt{\log{x}}\log{x}=8\log{10} \\ \\ \log{x}=t \\ \\ √(t) * t=8 \\ \\t^{(3)/(2)}=2^3 \\ \\ ( √(t) )^3=2^3 \\ \\ √(t) =2 \\ \\ (√(t))^2 =2^2 \\ \\ t=4


\log{x}=4 \\ \\ 10^{\log{x}}=10^4 \\ \\ x=10^4
User Udara Herath
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